nth roots of a complex number,大家都在找解答。第2頁
,nthRootsofComplexNumbers.ThisimportantformulaisknownasDeMoivre'sformula....Soifthentherootsofaregivenby$-displaystyler^1/n}-left(-cos-left(-frac-theta+2k-pi}n}-right)+i-sin-left(-frac-theta+2k-pi}n}-right)
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nth root | nth roots of a complex number
nth Roots of Complex Numbers | nth roots of a complex number
nth Roots of Complex Numbers. This important formula is known as De Moivre's formula. ... So if then the roots of are given by $-displaystyler^1/n} -left ( -cos -left ( -frac-theta + 2k -pi}n} -right ) + i -sin -left ( -frac-theta + 2k -pi}n} -right ) Read More
Determining the Nth Roots of a Complex Number | nth roots of a complex number
This video explains how to determine the nth roots of a complex number. http://mathispower4u.wordpress.com/ Read More
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Finding the nth Roots of a Complex Number | nth roots of a complex number
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To evaluate the nth root of a complex number I would first convert it into trigonometric form: z=r[cos(θ)+isin(θ)] and then use the fact that: Read More
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